Trigonometric Equations with Reciprocal Functions

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Example: Solve the formulafinding all solutions 0-360 degrees.

The expression factorises into

We follow the normal rule for quadratics by setting each factor equal to 0 and solving.

and

There are no other solutions in the range 0 – 360 degrees.

Example: Solve the formulafinding all solutions 0-360 degrees.

The expression factorises into

We follow the normal rule for quadratics by setting each factor equal to 0 and solving.

andand

and

Example: Solve the equationin the range 0 – 360 degrees.

or

or

oror

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