Not all suvat questions can be solved with a single application of the suvat formulae. Sometimes two applications are required, simultaneous equations are formed and these must be solved.
A particle starts from rest at a point O. It accelerates uniformly to a pint Pin 2 seconds, at which it has speed u. It continues to accelerate with the same constant acceleration to a point Q in a further 3 seconds. at which it has speed v. PQ=5m. Find the speed at P, the speed at Q and the distance PQ.
A diagram is drawn.
The acceleration is constant. Call it k. The final speed at P for the motion OP equals the initial speed at P for the motion PQ. Call it c.
Apply suvat to the motion OP.
Application of the equationgives (1)
Apply suvat to the motion PQ.
Use the equationto give
Sub (1) into (2) to give
Then from (1)